AC charger for NiCd AA battery?

Hi all,

I have a device which is powered by a solitary 1.2V 800 mA NiCd cell. An AC wall charger (5VAC @ 180 mA) is used to charge the cell. This is done via a simple half-wave rectifier that is built in to a small circuit board inside the device. The battery sees about 90 mA (true RMS).

It seems strange to use a hard-to-find AC power source rather than a commonly available DC wall adapter to do this job. Particularly since the built-in circuit simply rectifies the signal anyway. Any thoughts on why a product would use this approach?

Reply to
Borrall Wonnell
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A half-wave rectifier would provide a crude form of "pulse charging" which (at least in more refined forms, so perhaps it helps here) appears to be better for NiCad lifespan than a straight DC charge.

If they wanted that and are nickel and penny pinching like Jeorg ;^) an "easy for them to find since they buy large piles of them" AC supply and a diode might be cheaper than a DC charger & parts to pulse charge from DC.

--
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Reply to
Ecnerwal

=20

Very crude. Unfortunately the product was discontinued and repair parts ar= e nearly extinct. I found a 400 mA adapter which could be used but then I'= d need a larger capacity cell to maintain C/10 charge rate. No problem for= NiMH but impossible in NiCd world.

The stock battery has welded tabs with crimped ends that slide over rigid += /- terminals on the circuit board, holding the battery in place. I haven't = seen this before and I haven't found any batteries with welded crimp-style = tabs. Could be a pain to find a replacement, so I may bypass the battery a= ltogether and power directly at 1.5V. Will be ugly because the existing te= rminals are button contacts that mate with the charging dock.

Reply to
dbonnell

s

s are nearly extinct. =A0I found a 400 mA adapter which could be used but t= hen I'd need a larger capacity cell to maintain C/10 charge rate. =A0No pro= blem for NiMH but impossible in NiCd world.

+/- terminals on the circuit board, holding the battery in place. I haven'= t seen this before and I haven't found any batteries with welded crimp-styl= e tabs. =A0Could be a pain to find a replacement, so I may bypass the batte= ry altogether and power directly at 1.5V. =A0Will be ugly because the exist= ing terminals are button contacts that mate with the charging dock.

could find room inside for a bit of electronics? you can get many different small flat lipo batteries and single chip chargers that just need 5v in but that is 3.7V nom. so you need a bit more than just that

-Lasse

Reply to
langwadt

nearly extinct. I found a 400 mA adapter which could be used but then I'd need a larger capacity cell to maintain C/10 charge rate. No problem for NiMH but impossible in NiCd world.

terminals on the circuit board, holding the battery in place. I haven't seen this before and I haven't found any batteries with welded crimp-style tabs. Could be a pain to find a replacement, so I may bypass the battery altogether and power directly at 1.5V. Will be ugly because the existing terminals are button contacts that mate with the charging dock.

Build a simple current limiter to charge at C/10 (80 mA):

------- +6 ---Vin| LM317 |Vout---+ ------- | Adj [16R] | | +-----------+ | + [Batt] | - Gnd ---------------------+

Note that Vin is _6_ volts in the above. With a 16 ohm resistor, you'll get a bit over 78.125 mA constant current. The resistor will dissipate ~102 mW, so a 1/4 watt gives a good margin. The circuit does not "care" that there is a diode in series with the battery inside the device, it still produces ~ 80 mA constant current. If you drop Vin down to 5 volts, that internal diode may become a problem as the 317 could become "headroom starved".

You could use a higher Vin - if you do, more heat will be dissipated in the 317. Dissipation in the 317 is P = (Vin - Vout) * .08 and Vout = 1.28 + Vbatt

Dissipation in the resistor is constant regardless of Vin.

Ed

Reply to
ehsjr

On Friday, June 22, 2012 9:38:06 AM UTC-7, (unknown) wrote: [charge to a NiCd cell, circa 90 mA desired]

...

nearly extinct. I found a 400 mA adapter which could be used but then I'd need a larger capacity cell ...

Two solutions:

1>Find a smart charger for an AA NiCad cell and clip it onto the battery whenever you need it charged ( this will require you to bypass the rectifier and/or use other connections than the socket on the device). Beware, many chargers only charge TWO CELLS IN SERIES.

2>Use any-old-AC low voltage transformer, preferably in conjunction with a timer (10 hours charge, then shut it off) with a series limit resistor sized so it gives you a

90 mA charge.
Reply to
whit3rd

rts are nearly extinct. =A0I found a 400 mA adapter which could be used but= then I'd need a larger capacity cell ...

whenever you need it charged

ctions than the socket

.

a timer (10 hours

=A0you a 90 mA charge.

or a dc one, doesnt matter which walwart & resistor is the sensible option.

NT

Reply to
NT

a timer (10 hours

you a 90 mA charge.

Won't using a series resistor also reduce the voltage?

For now I'm just going to replace the battery using one of the suggested id= eas. At some point I'd like to do one of two things:

1) Convert the device to use external power (no battery). Run at about 1.5= VDC internally after using a regulator to drop from 5V DC external input. 2) Dual use...allow the device to run on external power or on battery power= . When connected to external power, battery is being charged. The only ci= rcuits I've seen for this use diodes which would probably mean sub-par oper= ation due to voltage drop. There's very little room inside the device, ext= ra circuitry is probably only a pipe dream.
Reply to
dbonnell

timer (10 hours

you a 90 mA charge.

Yes, of course. The implication of using any-old-wallwart is that it has to be greater voltage than the battery, you MUST reduce the voltage or your battery will not just charge, but charge, overheat, explode.

Reply to
whit3rd

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