Dear friends,
I have got an AC current detecting circuit. But I failed to understand. Can anyone help me? Thanks a lot in advance! [url=
It seems that the circuit between the input node SI and node 8 is useless. Anyone agree with me?
And what is the capacitors C19 and C24 for?
:Dear friends, : :I have got an AC current detecting circuit. But I failed to :understand. Can anyone help me? Thanks a lot in advance! : [url=
You need to learn to copy and paste the correct url link.
On Fri, 30 Jan 2009 00:07:55 -0800 (PST), " snipped-for-privacy@gmail.com" put finger to keyboard and composed:
The voltage at U4A-1 = SI/2 since R1 and R2 form a potential divider.
The voltage at U4C-9 = voltage at U4C-10 (if op-amp is operating in linear region).
Therefore voltage at U4C-8 = SI.
So it would seem that U4A and U4C are functioning as a unity gain buffer with a 10K input impedance, in which case I don't understand why they are needed, either.
They reduce the gain of the high frequency components in the signal.
- Franc Zabkar
Thank you very much!
The Capacitors C19 and C24 are for the stability of the > On Fri, 30 Jan 2009 00:07:55 -0800 (PST), " snipped-for-privacy@gmail.com"
=C2=B7=C3=96, " snipped-for-privacy@gmail.com"
/Have something to add? Share your thoughts — no account required.
Ask the community — no account required