12v to 3v

Can somebody please give me assistance with a circuit to power from 12v a variable 1.5 to 3v circuit. Presently the small fan is powered by 2 x D cells and runs for around 6 hours. I would like to have a potentiometer that goes from 1.5 to 3.0v. The fan will be finally powered from a 12v SLA battery charged from a solar panel.

Thanking you in anticipation for assistance.

Reply to
Maxamillion
Loading thread data ...

solar

How much current does the fan require? What is its specified operating voltage?

Reply to
Lord Garth

formatting link
will give direction and get back to us if you are confused ( low voltage section)

Reply to
atec77

I don't know how much current the fan takes. I wonder what the capacity of D size batteries is? Googling at the Ah capacity of D size carbon zinc batteries, and the period the batteries currently last, I would assume the fan takes 1/2 amp, but lets work on 1.0A for safety. The specified operating voltage is 3.0v and normally powers from 2 x D cells. As this will be powered from a sealed lead acid battery with a small solar panel, the voltage supply will reach 14.3v.

Reply to
Maxamillion

Yes, I am confused as the one that looked like it could apply the link was dead.

What I would like is a list of a few components and send me on my way to Jaycar and then to solder it together.

Reply to
Maxamillion

On Sun, 01 Jul 2007 21:47:38 GMT, "Maxamillion" put finger to keyboard and composed:

If the fan current is less than 500mA, then you should be able to modify just about any mobile phone car adapter/charger. In fact I've done something like this for a fan inside a DVD player. Many of these adapters use a Motorola PWM IC, MC34063, which can regulate down to

1.25V. You'll just need to modify one resistor.

- Franc Zabkar

--
Please remove one 'i' from my address when replying by email.
Reply to
Franc Zabkar
500mA is a little tooooo minimalist for my liking. I would rather spend the couple of extra dollars and make it more bullet proof and go for 1.0A. These need to be reliable. Have the space of the 2 x D cells to fit the electronics in, and the cover for the batteries will place the potentiometer. I also need it to be variable 1.5v to 3.0v

Reply to
Maxamillion

You could try this circuit:

formatting link

It's a basic PWM speed controller. As shown, the output will vary from 5% to

95% of the 12v supply. You want 10% to 25% - read the circuit explanation where it talks about the potentiometer - by working out the ratios, you can reduce the size of the the potentiometer and add a fixed resistor to each side of the pot to limit its operating range.
Reply to
Poxy

Poxy looking for something a little simpler. Something like using one of those three pin voltage regulator chips with a few extra components. I am familiar with PWM and is really over kill for this situation.

Reply to
Maxamillion

use PWM, it's easier and will give the same effect.

OTOH, 12V fans are easily available, some even have speed control built in. I've got one from an old PC powersupply with a temperature sensor attached, I could replace that with a variable resistor to have a speed control.

Bye. Jasen

Reply to
Jasen Betts

Normal three-terminal regulators will be very inefficient in dropping a nominal

12V supply to 1.5-3V, and givne that the 12V battery is solar-charged I'd expect you cant afford the 25% efficiency.

You really DO need to go switchmode for any sort of decent efficiency, or PWM.

My personal choice would be an MC34063 and an external transistor if required for the load current.

Reply to
budgie
25% efficiency would be worse than using a resistor - yes/no?

Could I use something like a 2N3055 with a few bits and pieces?

Reply to
Maxamillion

A potentiometer by itself won't be much good, but if you tie it up with an LM 317 regulator circuit it will be fine.

Or there are more sophisticated motor speed circuits that use pulse width modulation -- check DSE or Jaycar for kits.

Reply to
Peter Parker

It is what's needed , if you scrub off 9 vots dc at one amp thats a lot of wasted energy the solar unit has to make , a simple switch unit save most of the wasted energy and so less light/energy will keep things running .Use the circuit or somthing like it .

Reply to
atec77

On Mon, 02 Jul 2007 06:45:55 GMT, "Maxamillion" put finger to keyboard and composed:

As suggested elsewhere, you could add a cheap transistor to the circuit to handle the extra current.

See the application circuits in the datasheet:

formatting link
formatting link

A pot in place of, or in addition to, a resistor can give you the 1.5V to 3.0V range. Having said that, if your fan is a brushless type, then it may not run reliably at reduced voltages, nor will it tolerate direct PWM control as suggested elsewhere in this thread.

- Franc Zabkar

--
Please remove one 'i' from my address when replying by email.
Reply to
Franc Zabkar

25% efficiency IS what you get with a linear reg or a resistor, or any other non-switching method of losing the excess volts. They all do the same.

YOU get to decide if 25% is something you can afford, THEN the decison as to switching-vs-linear can be made very simply.

Reply to
budgie

Max sounds like a lost cause - for every good bit of advice he's been given, he's come back and either rejected it, called it mickey mouse, or passed over it.

Argusy

Reply to
Argusy

Troll ?

Reply to
atec77

Max is far from a lost cause, and most appreciative for the replies. You see a little knowledge is dangerous, and was under the impression that if you used a 3 pin regulator or transistor you did not get the amount of wasted power like you do using a resistor.

I did investigate the options in kits at Jaycar and DSE this morning, but nothing really suitable.

I am going to get one of the units this afternoon and see if we can adapt a

12v 80mm Jaycar fan to fit in place of the 3v fan.

Sincerely thanks all who replied.

Reply to
Maxamillion

a

You get the easiest build by stripping a mobile cell charger as was earlier suggested.

Reply to
Lord Garth

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.