This is self assigned homework, so don't bother if this circuit is impract ical. I'm just following the basics.
With reference to a common emitter degenerated linear amplifier with partia l bypassed emitter resistor (figure 2.39 of Arts of Electronics 2nd Ed.), I 'm trying to figure out the value in Farads for the emitter bypass capacito r, for an audio amplifier (smallest frequency of interest of 20Hz).
In my design the un-bypassed emitter resistance is
r_E =20 Ohm
Quiescent current I_CQ is 2.5mA, so the BE junction inner resistance r_e is roughly V_T/I_C =25/2.5=10 Ohm
The book states that "the bypass capacitor is chosen by making its impedanc e small compared with r_e", but in that case did not deal with the addition al un-bypassed resistance r_E.
By introducing r_E, I guess the previous sentence should be rephrased with "the bypass capacitor is chosen by making its impedance small compared wit h r_e+r_E =10+20=30 Ohm".
Now, the book deals with a lowest admitted frequency of 650Hz, but in my ca se f_c is 20Hz.
So I need a capacitor whose impedance @20Hz is smaller (lets say .. ten tim es smaller?) than 30 Ohm:
Z_C (f_c) =1/(2 pi f_c C)