JVC RX-707V component needed

Apr 05, 2007 3 Replies

I jumped the bad fuse on this unit and smoke quickly came from this component on the board.



It looks like a ceramic 1 inch shoebox. It has three leads and is marked: A (trademark?) 3w 0.22 ohms 1 D 2.



Is there any hope replacing this, (finding), and is this just a symptom of another problem.



I've looked at Radio Shack, Quest, etc. but I obviously wish it were a simple resistor.



I hope you can help me find one.



Thanks



Whilst these are available, you can just as easily use two separate R22 resistors. However, this will not be the end of the problem. That double resistor is the emitter resistors for the output pair, so at a very minimum, these transistors will be shot, and very likely, their drivers and maybe pre-drivers, as well as the bias compensation transistor, and probably several other resistors in the output pair's base drive coupling. This sort of failure is not to be treated lightly, and at a bare minimum, you will need a set of schematics, a good multimeter, possibly a 'scope, a deep wallet, and loads of patience ...

Arfa

Thanks Arfa, I guess it's time for Best Buy. It's complicated enough to connect a receiver to a TV, CD, tape, mp3, and a computer. I'll miss this unit. I read about 150 posts. I'm amazed that anyone works on home electronics anymore except for a hobby.

Tools & cash needed, plus patience! Well put.

If you go at the stuff with the right tools, and enough years' experience, there's still good money to be made from it - especially if you can get hooked into trade warranty repairs, which pay a fixed amount whether you get a fix or not, but I take your point. As long as there is only one or two of you doing it in an area, then it's still ok. As soon as you are in competition with more than a couple of others, then work becomes thinly spread these days, and it gets to be a struggle. If you can find a specialist niche it helps.

Arfa

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required