I hope this isn't too dumb a question.
I have an IC that requires a +5 and -5 volt supply. My method would be to use a centre tapped 12v transformer, two rectifiers, a
Guessing that this might be called a symmetrical power supply my googling has found this
"Periproct" schreef in bericht news: snipped-for-privacy@bt.com...
I'm not aware of a more simple solution. The only thing that may give problems is heat. I'd prefer a 2x8V or 2x9V transformer to reduce the heat to be dissipated in the regulators. It - of course - also depends on the required current.
petrus bitbyter
Try a +5 to -5 chip from a single +5 volt supply if the current requirement for the -5 V is not too high. Look at:
If it works, don't fix it. :-)
If you use the "two-way symmetric" from
Don't go with special/exotic chips unless it's intended as a learning exercise. :-)
Good Luck! Rich
I think I'll do that and bung a 7805 and 7905 on the end of it.
Thanks to all who replied. My apologies if I posted that question in the middle of another thread cos I can't see it unless I do a search for it. Regards, Nige
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