SMPS +/-5V about +50V supply.

I want a switch mode PSU which will give me two ~2A outputs at 5V above and below a nominal +50V (say +40V to +60V) DC supply, ie +55V and +45V from +50V.

I can probably work out some fairly clunky ways of doing this, but it seems possible that there's some topology particularly suited to this type of thing.

Any thoughts?

Cheers

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Clive
Reply to
Clive Arthur
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I'm a big fan of DC-DC converter modules; two isolated 10-watt regulated 5V modules would do the job. If you want to roll your own dc-dc converter, use a standard transformer type, rather than something inductor based.

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 Thanks, 
    - Win
Reply to
Winfield Hill

Thanks, Win.

I like the COTS modules too, but this has to be hand-rolled to work at

180'C. I should have mentioned that.

Cheers

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Clive
Reply to
Clive Arthur

You signed up to work in a oil drilling hole? I hope you are getting paid by the hour

Reply to
bulegoge

Do the 5 volt offsets need to be regulated?

Here are some old open-loop rail boosters.

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John Larkin         Highland Technology, Inc 

lunatic fringe electronics
Reply to
jlarkin

I like to use coupled inductors. They're available in triple and quad-winding versions. You regulate the output of one secondary, and the other two can go along for the ride, good to maybe 5%, or 10% if there are extremely unbalanced currents. I'd buck a 5-volt supply from 50V to start the process; and run transformer near 50% for good 20W efficiency.

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 Thanks, 
    - Win
Reply to
Winfield Hill

Thanks.

I could use a ground referenced 5V too, so that sounds like a buck converter with two extra 5V windings for the 50V +/-5V supplies. Regulation on those isn't critical, so that looks like a winner.

The cheque's in the post.

Cheers

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Clive
Reply to
Clive Arthur

I didn't suggest a single stage converter, because you wanted 10W from each extra 5V output. A 20W 50V to 5V buck is a bit of a beast on its own, needing 4A output, and hence it's switching 4A at 50V for 10% of the time. It needs its own special inductor, especially at 180C. Then you can use a standard coupled inductor, running at 50% to make an efficient isolated dual 5V 2A outputs.

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 Thanks, 
    - Win
Reply to
Winfield Hill

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