I have a pulse which I want to limit to a maximum length.
Using a 555 monostable with a differentiator at the input (the standard one with a BJT inverter, 10k + 10 nF + 10k filter, provides a "maximum length" pulse when triggered by a positive polarity pulse. This can be used with an external and-gate to limit the original signal to this length.
My question is - can this external and-gate be removed by cleverly connecting the 555 reset-input to the original signal, given that the polarity of the incoming signal is positive (i.e. at GND when inactive). Maybe someone here has seen this type of circuit before.
This would keep the 555 in reset until the input signal activates, then the output will go high until the timing is done (pulse reached the maximum length) OR the input signal goes low.
I'm not so sure about the allowed setup time of trig after reset ->
high though, I can't find this speced in the datasheets I've looked at. I need to know that the differentiators pulse will have sufficient hold to trig at the same time as the reset is lifted... spice- simulating with a model is not enough either since they are often just "functionally equivalent".
If the idea is inviting trouble, I guess I'll just put the and-gate there - it just seemed like a nice way to solve a simple problem and reducing the BOM :) Perhaps there is a way to configure a 556 instead to do this task..
The input as you call it I assume is the trigger input (pin 2)? If so This input gets triggered with a sink signal that is 1/3 or less from the Vcc supply.. It is a PNP input and sinking is the only thing it understands.. The threshold input uses (+) to trigger it and it must be (2/3) or more of the Vcc to activate the threshold, which simply turns the output off and kicks in the discharge pin..
Your (+) trigger is not starting it at the raising, but at the falling of your signal, which is assumed to have a sink source..
If the output pulse becomes shorter than the signal pulse, this can lead to problems because this means that the TRIGGER input is still being held low, assuming that you understood what I said before and correct the input polarity... Unless the falling edge of the signal is really where you want it to trigger..?
If you are trying to short cut the signal by using a one-shot method, you need to gate the input, so not to cause problems with the discharge output of the timer, other wise you won't get a full discharge, or one that is reliable.
Most people use a decoupled capacitor pulse to trigger the input thus removing this issue..
If pulse output timing to be a fixed domain, regardless of signal width input, then triggering the TRIGGER input via a cap decouple to keep the DC component out of the picture, avoiding a collision timing with the finishing output and signal input, should get you some where..
This would at least allow the discharge output to do it's job on your timing cap.
On Mon, 13 Dec 2010 16:31:36 -0800 (PST), BW wrote:
--- If I understand you correctly, what you want is for the 555 to output a pulse of a certain width when an input signal goes high and/or to go low if the input signal goes low before the circuit times out.
That's easily done like this: (View in Courier)
+V>----------------+---------+-------+ | |8 | | +---+---+ [Rt] | 2|_ Vcc |3 | +-----+------|----O|T OUT|---|------> OUT |R1 |C1 |C2 | _|7 | [10k][100nF][0.1µF] | D|O--+ | | | 4|_ |6 | IN>---+-----|------|----O|R TH|---+ | | | GND | | | | +---+---+ [Ct] | | |1 | GND>--------+------+---------+-------+ _ What happens is that when IN goes high, R is forced high, releasing the 555's RESET and allowing it to trigger. _ However, the T is held low, momentarily, by the differentiator, R1C1, which triggers the chip and forces its output high. The length of time OUT stays high will depend on the values of Rt and CT as long as IN stays high longer than the timeout period.
If it goes low before the circuit times out, the chip will be reset and the output will be forced low.
C2 is used to decouple the chip from the supply and should be mounted directly across pins 1 and 8, but if tyou use a CMOS 555 (7555) it can be omitted.
If you don't already have it, LTspice is free and available at:
formatting link
and if you care to simulate the circuit, here's the circuit list:
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