Induction melting of steel - melting time calculation

Dec 18, 2005 20 Replies

Hi James, sorry for the late reply I don't hang out on the group these days.

I just did a ball park calculation using heat capacity of steel roughly

500J/kg/K ie. 500* 1500 * (3.5/2.2) = 1.2MJ; the 0.1 error is because I did it the calc in my head.

I (knowingly) didn't include the latent heat of fusion for the ballpark calculation. In retrospect I probably should have because it is significant. I think for iron/steel Lf = 250kJ/Kg which comes out to

250k*(3.5/2/2) = 0.4MJ. That should be added onto the 1.2MJ giving a total of 1.6MJ (45% higher than my rough estimate).

James H. wrote:

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