In the same way that we have easy conversions for dealing with sine waves such as RMS Current = I peak / SQRT(2) and I ave = 2 * Ipeak / PI, I would like to know if anyone can help with this question;
Consider two bridged class B (single supply) amplifiers driving a load, the load is connected between each amplifiers output. The power supply is fed through a large inductor into a large reservoir capacitor.
For the sake of argument lets say the peak output current is 4 Amps. This makes the average current 4 x 2 / PI Amps, and this is the [constant] current in the inductor. The ripple current in the capacitor is the difference between this average current and the instantaneous current being supplied into the load. I get the RMS ripple current as 0.31 Ipeak (using a spreadsheet) but am not sure how to do the maths to get this answer. Can anyone help?