>30V output AND 0V offset from a single op-amp?

Apr 26, 2006 3 Replies

CA3140 data sheets show that the output can approach the positive rail and (allegedly) reach the negative rail. This might be false. On a single rail supply the offset cannot be trimmed to get a true zero output, you MUST have some negative.



I want to measure up to 30 watts at 1W/V from a thermopile sensor, on a multimeter, so my idea is a split rail supply whose total is 34 volts, with



30 volts on the positive side and just a few hundred mV for negative, to

get through-zero adjustment for offset error.


Will this work without frying the IC? Can anyone suggest common, low price, good performing IC's for this? It doesn't have to be a single rail op-amp, it just has to accept a VERY asymmetrical split rail. I'm hoping the LF411 or LF412 (with external offset trim) can do this.


I can make the dual supply stage, that's not the tough bit, but I'd like some advice about the extreme asymmetry I want for the gain stage. (Both will hopefully be workable from one dual op-amp IC).


-------------------------------------------------------------------------- PS. Sorry about the repost, but I really want some help here, and my last post got entirely lost behind the mark-up debate. I've reduced this post a LOT to try to gain some attention to it. :)

On Wed, 26 Apr 2006 01:00:11 GMT, Lostgallifreyan put finger to keyboard and composed:

Why not just use a resistive potential divider to reduce the input to a manageable level? Does the source need to see a high impedance, ie will it be unduly loaded by a potential divider?

- Franc Zabkar

Please remove one 'i' from my address when replying by email.

Franc Zabkar wrote in news: snipped-for-privacy@4ax.com:

Sorry, I nearly missed this one. :)

It's not the input that's the problem though, that's lower than +3V. What I was after was up to +30V output for measuring on a single range of a voltmeter. I was concerned that dual rail op-amps might only be designed for symmetrical supply rails, and might fail if ground was biased almost to negative while output was driven close to positive rail.

I reposted this in simpler form when this post appeared to get lost, with subject "How asymmetrical is an op-amp supply allowed to be?"

I've been told there by Tim Williams that any op-amp will allow a strongly biased ground, just 2 volts or so above negative, and still allow an output to get close to the positive rail even with max supply voltage; he says that both transistors in the output stage (and presumably the others) must be able to handle the full supply voltage.

If this is all I need to consider when using an LF412 with the small negative voltage to help zero the offset to my ground (made by the first stage in the op-amp and two resistors as potential divider), then the question is answered. :)

On Thu, 04 May 2006 10:47:43 GMT, Lostgallifreyan put finger to keyboard and composed:

Sorry, brain fart. Sadly they're getting more frequent as I get older.

- Franc Zabkar

Please remove one 'i' from my address when replying by email.

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