- posted
13 years ago
Electric fence operation problem
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- posted
13 years ago
I would expect the output to be at fault when you take into consideration all the short circuits electric fencing can encounter.
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- posted
13 years ago
corroded
diode
of
output
never
step
neon.
that
proper
but
I've disconnected the HV section and no difference. The o/p of the intermediate is 4V pk-pk pulses with designed 3uS osc i/p. Barely enough to exceed the bank of 6 seriesed rectifier diodes . Inductances of the intermediate Tr are 0.1mH and 84mH . i'm wondering if there is shorted turns, will try and find some SMPS to try in reverse. The output Tr is E-I iron cored not HF on closer looking
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- posted
13 years ago
d
de
f ter
pn.
t r tSounds like the unit may have been hit by a lightning surge. I have seen a few and usually all the electronic parts are blown as well at the transformer winding insulation punctured. To your question of intermediate voltage, I would suspect something in the 50-100V range. I imagine that there is a storage cap since your description sounds like a C-D circuit, so one would expect the intermediate voltage to be around 60% of the cap voltage rating, if it is an electrolytic. Neil S.
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- posted
13 years ago
diode
never
neon.
Sounds like the unit may have been hit by a lightning surge. I have seen a few and usually all the electronic parts are blown as well at the transformer winding insulation punctured. To your question of intermediate voltage, I would suspect something in the 50-100V range. I imagine that there is a storage cap since your description sounds like a C-D circuit, so one would expect the intermediate voltage to be around 60% of the cap voltage rating, if it is an electrolytic. Neil S.
&&&&&&&I'd not thought of that route, will desolder the C, script on the wrong side. I'd expect the dual monostable IC to be knocked out with lightning
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- posted
13 years ago
Would be nice to know the normal pulses of the driver circuit. It is possible a shorted device in the output could damage the driven stage.
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- posted
13 years ago
d
de
f ter
pn.
t r tNo manufacturer information aailable??
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- posted
13 years ago
On Wed, 7 Jul 2010 14:46:36 +0100, "N_Cook" put finger to keyboard and composed:
B20 Dry Battery Energiser:
If the above is your electric fence device, then the Stored Joules rating of 0.2J should enable you to calculate the voltage across the HV capacitor.
E = 1/2 x C x V^2
so V = sqrt (2 x 0.2 / C)
- Franc Zabkar
-- Please remove one 'i' from my address when replying by email.
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- posted
13 years ago
The cap is 1uF , 280V ac rating. From the .5*C*V*V that comes to 630V, so something awry there. No more than 250V m 60% of likely DC rating, and I would have thought more like an equal split between 12V and 1800V so about 150V, transformers are much the same size if that is anything to go by
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- posted
13 years ago
If I ever get this thing working properly , how to check the average current drain? I am thinking 12V supply >- ammeter >- bank of 20V Cs summing to about 0.1F
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- posted
13 years ago
that is a current limited 12V supply , not a car battery of course
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- posted
13 years ago
On Thu, 8 Jul 2010 08:24:40 +0100, "N_Cook" put finger to keyboard and composed:
It may appear counterintuitive, but a rating of 280VAC/630VDC for a metallised polypropylene or polyester capacitor is not uncommon.
See the Axial Metallized Polypropylene Capacitors on page 10 of the first PDF.
In particular, there is a 1uF, 280VAC/630VDC cap, p/n ARPM10563KYUKZZ.
- Franc Zabkar
-- Please remove one 'i' from my address when replying by email.
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- posted
13 years ago
Find a cow, sheep or horse willing to test it.
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- posted
13 years ago
current
0.1FI don't think asking one "hoo moony mooliemoomps dooze this moozapper gizmoo take" would get very far
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- posted
13 years ago
On Thu, 8 Jul 2010 08:24:40 +0100, "N_Cook" put finger to keyboard and composed:
If the device is designed to output its rated energy over a 9V-12V supply range, then one would expect that the dump capacitor's voltage would be regulated. Otherwise the variation in the stored energy would be (12/9)^2 = 1.8X.
Is there any voltage feedback from the dump cap back to its charge controller? I'd expect to see a resistive potential divider feeding one input of an error amp (comparator?), and maybe a 5V or 2.5V reference on the other input. You may be able to compute the voltage from the resistance values.
- Franc Zabkar
-- Please remove one 'i' from my address when replying by email.
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- posted
13 years ago
more
There is a chain of 3.3M resistors for feedback , I suspect it would change the 1.5KHz multivibrator rather than the 300KHz one. There is also the 1 to
2 second repetition cycling, perhaps 3 multivibrator package, also unreadable marking- Vote on answer
- posted
13 years ago
On Fri, 9 Jul 2010 08:45:56 +0100, "N_Cook" put finger to keyboard and composed:
I would expect that the multivibrator would have an internal reference voltage which it would compare against the voltage on the resistor at the bottom end of the potential divider. The IC's reference voltage may appear on one of its pins.
I would locate where the divider feeds into the IC, and determine the values of all the resistances in the chain. Then measure the voltages on the pins on either side of the feedback pin. If you can supply this information, then perhaps it will help ascertain the capacitor voltage.
- Franc Zabkar
-- Please remove one 'i' from my address when replying by email.
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- posted
13 years ago
Hi,
I found this schematic (circuit diagram) somewhere on the net, is it anything like your one ?
Ian.
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- posted
13 years ago
corroded
of
output
stage
step
that
proper
than
but
explain
The 'IV' and HV stage is very similar, this one has a lot of SM so a bit more distributed for the higher voltages, ie tripling up of diodes and Rs
Do you have the URL of the text relating to that pic Search on that site just enigmatically/awkwardly/insultingly returns "The answer given for the random question was incorrect."
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- posted
13 years ago
Googled for it