Prove That's Impossible To Increase Surface Area of Fluorescent

I'm almost certain this proof has been done before in one of those gradient divergence and curl fields classes.

To start the I'ld make some simplyfing assumptions. Reduce it to a 2d problem, the tubes are square and the light only exits the glass surface in a normal direction.

No matter how you arrange the squares or any reflective surfaces . . .

What they need is a one way mirrored glass surface. Just as CO2 keeps the IR light in the biosphere this surface would keep the white light from reentering the tube.

Bret

Reply to
BretCahill
Loading thread data ...

Bret, in actuality (real physics) there is no such thing as a one way mirror.

Partially silvered mirrors simply appear that way as a result of the light attenuation of the images passing though the partially mirrored surface making these images appear to vanish on the side of the mirror while highlighting images on the side more brightly illuminated.

What you appear to need for your purposes is a light rectifier, which in reality doesn't exist, although there are some liquid crystal light switches that can come pretty close.

Harry C.

Reply to
Harry Conover

problem,

reentering

What would one use a "light rectifier" for if it did exist ? Lasers , probably (and the optical equivalent of a C/W multiplier) ?

-A

Reply to
Andre

Apparently fiber optics can be used to make all the light in a folded or spiraled fluorescent tube available, although at a price.

This only proves the exact opposite of what I set out to prove.

In any event there is more to the low intensity of fluorescent light problem than large surface area. Large volume is the real problem.

Bret Cahill

Reply to
BretCahill

problem,

Nothing so trivial.

Creating free energy. Take a sealed box, make small box out of light rectifier. Place this inside the sealed box. Thermal radiation gets into the sealed box, but not out. It gets hotter, and you can run a heat engine off it, and heat the outside box without external energy input.

--
http://inquisitor.i.am/    |  mailto:inquisitor@i.am |             Ian Stirling.
---------------------------+-------------------------+--------------------------
 Click to see the full signature
Reply to
Ian Stirling

Hmmmmm If heat gets into but not out of the little box then where does the heat come from that heats the bigger box?

Reply to
Michael

The energy is the key. Energy is being transported in the form of photons. High or low energy is immaterial. The energy in one photon might be later transported as two lower energy photons. As long as ANY photon can get through a "light rectifier", it will have the capability of providing heat. What a light rectifier implies is that anything with any temperature or energy differential at all can operate an engine for free. However, this violates thermodynamics. Therefore, no light rectifier can exist. QED.

Cheers!

Chip Shults My robotics, space and CGI web page -

formatting link

Reply to
Sir Charles W. Shults III

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.