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Help with understanding this circuit

Lets say you have 2 capacitors of equal capacitance wired in series and this combination wired in series with a resistor, R1. Now, obviously you can find the equivalent capacitance of the 2 caps and the circuit becomes a standard RC deal.

But suppose that you place a load between the 2 capacitors. Say a resistor, R2. Basically, how do you model this circuit?

If the load were an LED, and the values correctly chosen, would it light at all?

Thanks

Reply to
Patrick Leonard
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this

resistor,

From what perspective? If you want to model it just as a series RC (i.e., what is the equivalent RC seen across the end nodes), it's the series combination of all these elements - the total resistance is R1 + R2, and the total capacitance is

1/2 C (where C is the value of each of the two equal caps), and that's that.

at

Initially, sure - but if connected to a DC supply, the LED will turn off just as soon as the capacitors are sufficiently charged.

Bob M.

Reply to
Bob Myers

In article , snipped-for-privacy@rogers.com mentioned...

You haven't given enough information to answer the question. Like which two points is the LED connected? Draw a ssimple diagram for us using courier font. If the voltage is less than about 2 volts, the LED will never light, no matter where you connect it.

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Watson A.Name - 'Watt Sun'

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