I wrote a VHDL program and loaded it into a Xilinx XC95108 chip , unfortunately , the chip's memory is unable to store the VHDL Program . The VHDL program size is too huge . I was wondering what's the maximum number of Flip-flops & Gates the XC95108 can store ? I need this information . Can anyone tell me ?
Thanks for the help .
Look in the data sheet.
The number of FFs should be simple. The number of gates is (much) more complicated.
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The 108 has 108 cells. Each has a FF.
Steve
One cannot load a VHDL program in a chip. What you load is a bitstream, which results from running first synthesis and then several implementation phases. If your design doesn't fit in a particular chip you know it when your implementation fails in one of the phases. When this happens you don't have a bitstream to load. So, I don't understand what and how you were trying to load?...
/Mikhail
Well, I ran all the programs ( running fc2,design manager ... )and implementation and all phases were successful.It's only at the last stage where I have this problem,the chip's memory size is too small to store my vhdl program.
By the way, the XC95108 has 108 cells , what are cells ? so the sc95108 can store 108 flip-flops ?
Thanks for the help.
You really should read the data sheet.
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The numbers in the suffix stand for macrocell count. So, a XC95108 woould have 108 MCs. A MC contains a register, PTA (product term allocator) and a switch matrix. You should read the datasheet for more info. Also a "chip's memory size" does not make any sense. The 9500s do not have any on-chip memory. Maybe you meant that the device is over-utilized?
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