I got a spreadsheet from Altera that lists the on-chip power supply bypass caps on an Arria II GX95 FPGA. I was kind of shocked to see 32 listed capacitors, most around 1 nf, but a Vcc_core (0.9 volt) cap of
501 nF. I was told that these caps are on-chip, not in-package.
Is that possible? 501 nF on an FPGA chip?
--
John Larkin Highland Technology, Inc
jlarkin att highlandtechnology dott com
http://www.highlandtechnology.com
Maybe attached to the top of the die with micro-C4s.
Cheers
Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
Well, that would give you the least inductance, for sure.
They used to sell DIP sockets with built-in bypass caps....which unfortunately had about an inch of lead length.
Cheers
Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics, Electro-optics, Photonics, Analog Electronics
160 North State Road #203
Briarcliff Manor NY 10510
hobbs at electrooptical dot net
http://electrooptical.net
When I designed 10 years ago the DUT power supply of an ATE family that's now testing all the processors that you're using I was given a 400nF figure. This cap was necessarily on chip since we were directly testing the wafer.
For the extreme case you can have both: embedded into the silicon plus additional under the lib.
The big processors are given for something like 100A/ns which you can't get with if you don't have that two level bypass to supplement the usual board level bulk...
The common method of marking capacitors, similar to the resistor stripe code, is two digits and an exponent of 10 in pF. Otherwise, the traditional tolerance for IC components was about 20%. (The ratio of parts on the same chip is much closer.)
Otherwise, the dielectric strength of SiO2 is about 25 MV/m (or 25V/um). At 1V you might make a capacitor at 40nm thickness. The relative dielectric constant is close (enough) to 1. Epsilon nought is about 9pf/m. C/A=epsilon nought/d=225pf/mm^2. So, about 2mm^2 would be enough.
If you could do it with a reverse biased pn junction, and I will guess that you can't, the relative dielectric constant of Si is 11.7.
Device on a chip are isolated by reversed biased pn junctions to the substrate. There should be a charge pump to get the substrate enough negative. (Remember when chips had a -5V power supply?) The capacitance, then, to the substrate through the reverse biased junction, depends on the thickness of the depletion region, which depends on the doping. Normally, you want that as low as possible, though.
That just created a whole new market for the Rogers Q-cap (TM). Those caps were big flat things the size of the socket with leads on opposite corners to match the TTL pinouts. You could also use them under an IC without a socket by sharing the same component holes.
As for on-BGA caps, your X-Ray inspection will show these quite nicely.
Sounds quite likely. The original DEC Alpha CPU had about 100nF on die, and that was in the 90s. Decoupling capacitors normally use gate oxide as the dielectric, so on more modern processes the capacitance could be greater. They might not use the thinnest gate oxide for the capacitors these days as the leakage current per area starts to get quite large with very low voltage transistors.
When using place and route tools to generate logic layout from the verilog, you can set up the tools to not leave blank spaces in the layout where no gates would fit, but to put in a decoupling capacitor cell instead. Because it is embedded within the logic it helps more than a big lumped capacitor off at the edge of the logic. If necessary, you can even tell the tools to put in a certain quantity of capacitors within the logic layout even if it would have been able to pack the logic a bit more densely without.
If the package has bondwires (or comparable series inductance in the power supply pins), then these can resonate with the on-chip decoupling, to form a parallel resonant circuit that presents the chip circuitry with a very high impedance at some RF frequency. In order to avoid this effect, I used to simulate with the package model and I would break the decoupling capacitor into smaller banks and put series resistors of various values in series with some of the banks of capacitors, so that the Q is low and the impedance is reasonable at all RF frequencies of interest.
I never drove those tools, I was mostly doing analogue stuff. I think it is a multi-stage process, the first stage could use "design compiler" from Synopsys, and then there are various other programs involved in the physical placement and timing verification which I don't really know about. Sorry I don't know the names of them. I know these were very expensive, presumably because they could save a significant percentage of the chip area, which translates into a significant amount of money saved on production.
Apparently it is done. There are patents for paving over the top of a chip with power distribution metalization, dielectric, and ground. The numbers make sense.
I'd just never heard of this before. It's mentioned in an Altera appnote. This is great, and largely negates their own silly guidelines for on-pcb bypassing, which we routinely ignored anyhow.
--
John Larkin Highland Technology Inc
www.highlandtechnology.com jlarkin at highlandtechnology dot com
Precision electronic instrumentation
It could just be that their parasitic extraction tool told them capacitance was 501.596683nF and Marketing didn't understand about significant figures.
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