on-chip bypass caps

I got a spreadsheet from Altera that lists the on-chip power supply bypass caps on an Arria II GX95 FPGA. I was kind of shocked to see 32 listed capacitors, most around 1 nf, but a Vcc_core (0.9 volt) cap of

501 nF. I was told that these caps are on-chip, not in-package.

Is that possible? 501 nF on an FPGA chip?

--

John Larkin         Highland Technology, Inc 

jlarkin att highlandtechnology dott com 
http://www.highlandtechnology.com
Reply to
John Larkin
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Maybe attached to the top of the die with micro-C4s.

Cheers

Phil Hobbs

--
Dr Philip C D Hobbs 
Principal Consultant 
ElectroOptical Innovations LLC 
Optics, Electro-optics, Photonics, Analog Electronics 

160 North State Road #203 
Briarcliff Manor NY 10510 

hobbs at electrooptical dot net 
http://electrooptical.net
Reply to
Phil Hobbs

If nothing else, I'd be very syspicious of any claims with that level of accuracy. My guess is a typo.

How big is the die? How thin would the insulator have to be?

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These are my opinions.  I hate spam.
Reply to
Hal Murray

I did a crude measurement of some of the balls on the FPGA, and estimated capacitances in the 10s of nF. That surprised me.

--

John Larkin         Highland Technology, Inc 

jlarkin att highlandtechnology dott com 
http://www.highlandtechnology.com
Reply to
John Larkin

Yeah, there could be discrete caps under the lid. But 32 of them?

It doesn't look like there are caps on/in the BGA carrier, which appears to be a 12-layer PCB.

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Cool, however they do it. Every chip should have internal bypasses.

--

John Larkin         Highland Technology, Inc 

jlarkin att highlandtechnology dott com 
http://www.highlandtechnology.com
Reply to
John Larkin

I vote for a typo. 501 and not 500 or 502? Or 480 or 520? They probably meant 1nF, or perhaps "5 delete" turned into "50" in front of a

1.
--

Tim Wescott 
Wescott Design Services 
http://www.wescottdesign.com
Reply to
Tim Wescott

Well, that would give you the least inductance, for sure.

They used to sell DIP sockets with built-in bypass caps....which unfortunately had about an inch of lead length.

Cheers

Phil Hobbs

--
Dr Philip C D Hobbs 
Principal Consultant 
ElectroOptical Innovations LLC 
Optics, Electro-optics, Photonics, Analog Electronics 

160 North State Road #203 
Briarcliff Manor NY 10510 

hobbs at electrooptical dot net 
http://electrooptical.net
Reply to
Phil Hobbs

When I designed 10 years ago the DUT power supply of an ATE family that's now testing all the processors that you're using I was given a 400nF figure. This cap was necessarily on chip since we were directly testing the wafer.

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Thanks, 
Fred.
Reply to
Fred Bartoli

For the extreme case you can have both: embedded into the silicon plus additional under the lib.

The big processors are given for something like 100A/ns which you can't get with if you don't have that two level bypass to supplement the usual board level bulk...

--
Thanks, 
Fred.
Reply to
Fred Bartoli

That was kinda hard to get around since someone for some reason had decided to put gnd and vcc at opposite ends of the chips

-Lasse

Reply to
langwadt

The common method of marking capacitors, similar to the resistor stripe code, is two digits and an exponent of 10 in pF. Otherwise, the traditional tolerance for IC components was about 20%. (The ratio of parts on the same chip is much closer.)

Otherwise, the dielectric strength of SiO2 is about 25 MV/m (or 25V/um). At 1V you might make a capacitor at 40nm thickness. The relative dielectric constant is close (enough) to 1. Epsilon nought is about 9pf/m. C/A=epsilon nought/d=225pf/mm^2. So, about 2mm^2 would be enough.

If you could do it with a reverse biased pn junction, and I will guess that you can't, the relative dielectric constant of Si is 11.7.

Device on a chip are isolated by reversed biased pn junctions to the substrate. There should be a charge pump to get the substrate enough negative. (Remember when chips had a -5V power supply?) The capacitance, then, to the substrate through the reverse biased junction, depends on the thickness of the depletion region, which depends on the doping. Normally, you want that as low as possible, though.

-- glen

Reply to
glen herrmannsfeldt

That just created a whole new market for the Rogers Q-cap (TM). Those caps were big flat things the size of the socket with leads on opposite corners to match the TTL pinouts. You could also use them under an IC without a socket by sharing the same component holes.

As for on-BGA caps, your X-Ray inspection will show these quite nicely.

--
Gabor
Reply to
Gabor

Or possibly the value from the part number, which is in pF. Two digits plus the number of zeroes to add, i.e. 501 would mean

500 pF. That would be rather small for core supply hold-up, though.
--
Gabor
Reply to
Gabor

Sounds quite likely. The original DEC Alpha CPU had about 100nF on die, and that was in the 90s. Decoupling capacitors normally use gate oxide as the dielectric, so on more modern processes the capacitance could be greater. They might not use the thinnest gate oxide for the capacitors these days as the leakage current per area starts to get quite large with very low voltage transistors.

When using place and route tools to generate logic layout from the verilog, you can set up the tools to not leave blank spaces in the layout where no gates would fit, but to put in a decoupling capacitor cell instead. Because it is embedded within the logic it helps more than a big lumped capacitor off at the edge of the logic. If necessary, you can even tell the tools to put in a certain quantity of capacitors within the logic layout even if it would have been able to pack the logic a bit more densely without.

If the package has bondwires (or comparable series inductance in the power supply pins), then these can resonate with the on-chip decoupling, to form a parallel resonant circuit that presents the chip circuitry with a very high impedance at some RF frequency. In order to avoid this effect, I used to simulate with the package model and I would break the decoupling capacitor into smaller banks and put series resistors of various values in series with some of the banks of capacitors, so that the Q is low and the impedance is reasonable at all RF frequencies of interest.

Chris

Reply to
Chris Jones

Just out of curiosity, which tools exist/do you use to go from verilog/VHDL to layout?

Pere

Reply to
o pere o

I never drove those tools, I was mostly doing analogue stuff. I think it is a multi-stage process, the first stage could use "design compiler" from Synopsys, and then there are various other programs involved in the physical placement and timing verification which I don't really know about. Sorry I don't know the names of them. I know these were very expensive, presumably because they could save a significant percentage of the chip area, which translates into a significant amount of money saved on production.

Chris

Reply to
Chris Jones

Apparently it is done. There are patents for paving over the top of a chip with power distribution metalization, dielectric, and ground. The numbers make sense.

I'd just never heard of this before. It's mentioned in an Altera appnote. This is great, and largely negates their own silly guidelines for on-pcb bypassing, which we routinely ignored anyhow.

--

John Larkin                  Highland Technology Inc 
www.highlandtechnology.com   jlarkin at highlandtechnology dot com    

Precision electronic instrumentation
Reply to
John Larkin

(snip)

If you are interested in which tools, you might be interested in:

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Which teaches how some of the tools work, though it is a little late to start now if you want a certificate.

-- glen

Reply to
glen herrmannsfeldt

Am 08.04.2014 22:09, schrieb Phil Hobbs:

I played around with a spectrum analyzer & tracking gen. and noted the results, waiting for Xilinx ISE some years ago.

Those funny sockets are at he end: <

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>

Cheers,

Gerhard

Reply to
Gerhard Hoffmann

It could just be that their parasitic extraction tool told them capacitance was 501.596683nF and Marketing didn't understand about significant figures.

Theo

Reply to
Theo Markettos

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