N Norman Contact options for registered users posted 16 years ago Fri, Sep 21, 2007 9:32 PM Reply toNorman Notify me about replies to my post Reply
J Jd. Contact options for registered users Vote on answer posted 16 years ago Sat, Sep 22, 2007 7:31 AM Reply toJd. Notify me about replies to my post Reply
I invalid unparseable Contact options for registered users Vote on answer posted 16 years ago Tue, Sep 25, 2007 5:24 PM Bardzo latwo: L [zwoje/Volt] = 48/S gdzie: S [cm^2] =sqr(P[VA]x1.1) dla wiekszych mocy dajemy 45 zamiast 48 ot cala tajna wiedza;) Reply toinvalid unparseable Notify me about replies to my post Reply