Question about this charge pump

I have some questions about this charge pump:

formatting link
This should give a gate voltage to nmos switch equal to 2Vdd, but i don't understand how does it....If i consider an input voltage equal to 0V,inverter gives Vdd,this voltage becames left nmos gate voltage,this charges C1 to Vdd . So, the voltage drop in C1 is equal to Vdd, in C2 is equal to 0.This procedure is wrong because it doesn't give the same results in figure...so how this circuit works? Thanks

Reply to
silusilusilu
Loading thread data ...

Somebody needs to explicate that diagram. One would assume that the mosfet pair forms a bistable multivibrator -- but then why are the gates connected to the sources? And what are n-channel mosfets doing at the top rail? If this is a well-known circuit, there ought to be links to some other pages that actually explain what's going on and have the components clearly labeled.

Reply to
Michael Robinson

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.