Bob
Bob
2 volts maybe; tiny schottky diodes.
Millivolts can heat up milliohms.
Ionizing a component? Do you mean vaporizing it?
John
-- Yup. I thought, initially, that it was 11, but after reading your reply and doing the necessary legwork I found that I was wrong and you were right. Thanks for your insight. :-)
messagenews:47310839$0$20630$ snipped-for-privacy@roadrunner.com...
I think you are wrong. I was told it was 47.5
Hi:
What is the maximum voltage possible *without* doing any of the following to any extent?:
Thanks,
Radium
the following
component
electronic component
i think 42 just might be the ultimate answer... but don't make a typo because it definately is not 32 , that is a bad #, because that destroys lots of stuff
robb
THis is quite easy. its 0.
But 42 is THE answer to all questions about the Universe.
At least it is the answer to all Radium ranti...pardon.. questions.
snipped-for-privacy@corp.supernews.com, "robb"
message
is a
apologies, had it backwards, not ultimate answer but *the* answer to *the ultimate question...* robb
While 42 is fine and well for most situations, I've always had a mysterious draw to 666. It has never let me down.
-phaeton
You said "dielectric strength."
Sure.
John
2 volts? Many CPUs cannot tolerate voltages above 1 volt without damage!
Beyond 70 Fahrenheit?
Naw. Plug your circuit into that and all you'll get are fire and brimstone.
messagenews:47310839$0$20630$ snipped-for-privacy@roadrunner.com...
That's only for small values of 47.5
Isn't the damage to the CPU caused by a mixture of excessively high temperatures and dielectric breakdown?
Also, dielectric breakdown [even without significant heat] damages flash RAM chips [which is why they don't last too long]. The electrons pierce the insulations within the chip.
How can a millivolt generate temperatures above 70 F in a milliohm? Both the voltage and the resistance are too small to generate such high temperatures. Right?
One millivolt across one milliohm is still one amp. What about several millivolts?
Current is still V/R, so 23 (another magic number) millivolts across a one inch length of #20 wire (about 1 mOhm) will produce 23 amps. And power is V*I, so you have about half a watt. Doesn't sound like much, but it's enough to melt the wire, especially if it is enclosed in thermal insulation. If you operate a 1/2 watt lamp in a well insulated box, the air inside will get well above 70F. Temperature depends on heat conduction and radiation. So, imagine how hot a tiny IC bonding wire could get with just
23 mV applied to it. Pow! Er! A "semiconductor" fuse...Paul
He didn't say "a millivolt", he said "millivolts". E.g. 100mV into 1mOhm =
100A * 100mV = 10W.A much smaller power dissipation can still produce high temperatures if the thermal resistance is high enough.
About 0.56V.
What do you do if the ambient is >70F?
Cheers! Rich
Thanks.
Thats okay. I just don't want anything inside to get damaged
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