Max voltage safe for all electronic devices?

  1. Bob

Reply to
BobW
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2 volts maybe; tiny schottky diodes.

Millivolts can heat up milliohms.

Ionizing a component? Do you mean vaporizing it?

John

Reply to
John Larkin

--
Yup.

I thought, initially, that it was 11, but after reading your reply
and doing the necessary legwork I found that I was wrong and you
were right.

Thanks for your insight. :-)
Reply to
John Fields

messagenews:47310839$0$20630$ snipped-for-privacy@roadrunner.com...

I think you are wrong. I was told it was 47.5

Reply to
sparky

Hi:

What is the maximum voltage possible *without* doing any of the following to any extent?:

  1. Exceeding the dielectric strength of any electronic component

  1. Generating temperatures above 70 Fahrenheit in any electronic component

  2. Ionizing any electronic component

Thanks,

Radium

Reply to
Green Xenon [Radium]

the following

component

electronic component

i think 42 just might be the ultimate answer... but don't make a typo because it definately is not 32 , that is a bad #, because that destroys lots of stuff

robb

Reply to
robb

THis is quite easy. its 0.

Reply to
Jon Slaughter

But 42 is THE answer to all questions about the Universe.

Reply to
Don Bowey

At least it is the answer to all Radium ranti...pardon.. questions.

Reply to
Sjouke Burry

snipped-for-privacy@corp.supernews.com, "robb"

message

is a

apologies, had it backwards, not ultimate answer but *the* answer to *the ultimate question...* robb

Reply to
robb

While 42 is fine and well for most situations, I've always had a mysterious draw to 666. It has never let me down.

-phaeton

Reply to
phaeton

You said "dielectric strength."

Sure.

John

Reply to
John Larkin

2 volts? Many CPUs cannot tolerate voltages above 1 volt without damage!

Beyond 70 Fahrenheit?

Reply to
Green Xenon [Radium]

Naw. Plug your circuit into that and all you'll get are fire and brimstone.

Reply to
Tom2000

messagenews:47310839$0$20630$ snipped-for-privacy@roadrunner.com...

That's only for small values of 47.5

Reply to
ehsjr

Isn't the damage to the CPU caused by a mixture of excessively high temperatures and dielectric breakdown?

Also, dielectric breakdown [even without significant heat] damages flash RAM chips [which is why they don't last too long]. The electrons pierce the insulations within the chip.

How can a millivolt generate temperatures above 70 F in a milliohm? Both the voltage and the resistance are too small to generate such high temperatures. Right?

Reply to
Green Xenon [Radium]

One millivolt across one milliohm is still one amp. What about several millivolts?

Current is still V/R, so 23 (another magic number) millivolts across a one inch length of #20 wire (about 1 mOhm) will produce 23 amps. And power is V*I, so you have about half a watt. Doesn't sound like much, but it's enough to melt the wire, especially if it is enclosed in thermal insulation. If you operate a 1/2 watt lamp in a well insulated box, the air inside will get well above 70F. Temperature depends on heat conduction and radiation. So, imagine how hot a tiny IC bonding wire could get with just

23 mV applied to it. Pow! Er! A "semiconductor" fuse...

Paul

Reply to
Paul E. Schoen

He didn't say "a millivolt", he said "millivolts". E.g. 100mV into 1mOhm =

100A * 100mV = 10W.

A much smaller power dissipation can still produce high temperatures if the thermal resistance is high enough.

Reply to
Nobody

About 0.56V.

What do you do if the ambient is >70F?

Cheers! Rich

Reply to
Rich Grise

Thanks.

Thats okay. I just don't want anything inside to get damaged

Reply to
Green Xenon [Radium]

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