I have an automatic opening trash can in the kitchen that runs off of batteries. I wanna run it with a wall wart. When the lid opens it draws more power than the 750 mA wall wart I tried using to power it could deliver. This makes sense. I don't want to use a bigger wall wart and I don't want to have betteries in it all the time to provide the current. I'm thinking instead of using a capacitor. If the current and voltage draw as well as the duration to open the lid is measured can that not be used to calculate the minimum size capacitor? And if not excessive maybe a cap that would open the lid three or four times in a row could be used in place of the 6 AA cells it uses now. Reasonable? Thanks, Eric
- posted
6 years ago