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Posted by Terminal Crazy on June 4, 2009, 1:56 pm
Hi guys, hope someone can help.

I've got a LM393 on a 12v supply measuring a thermistor. I've got it
switching around the right temperature but have a grey area where the
output ramps up brightening the LED until it switches fully on.

How do i increase the feed back so the output switches from 0 to 1 ?

TIA

--
Mitch

terminal_crazy@sand-hill.freeserve.co.uk
www.sand-hill.freeserve.co.uk/terminal_crazy


Posted by John Fields on June 4, 2009, 2:29 pm
On Thu, 04 Jun 2009 18:56:12 +0100, Terminal Crazy

>Hi guys, hope someone can help.
>I've got a LM393 on a 12v supply measuring a thermistor. I've got it
>switching around the right temperature but have a grey area where the
>output ramps up brightening the LED until it switches fully on.
>How do i increase the feed back so the output switches from 0 to 1 ?

---
You'll need to introduce some hysteresis by connecting a large-valued
resistor form the output to the + input.

Got a schematic?

JF

Posted by Terminal Crazy on June 4, 2009, 2:47 pm
> You'll need to introduce some hysteresis by connecting a large-valued
> resistor form the output to the + input.
thanks

I'd tried feedback to the +ve side of the sensor(on the -ve input) .
Presumably feeding back to the +ve input would raise it towards the +ve
rail ?

> Got a schematic?
I'll have a play with this first thanks.

--
Terminal_Crazy

Mitch - 1995 Z28 LT1 M6 terminal_crazy@sand-hill.freeserve.co.uk
Lancashire England http://www.sand-hill.freeserve.co.uk/terminal_crazy/

Posted by default on June 4, 2009, 6:06 pm
On Thu, 04 Jun 2009 19:47:27 +0100, Terminal Crazy

>> You'll need to introduce some hysteresis by connecting a large-valued
>> resistor form the output to the + input.

This is an op amp? A smidgen of positive feedback is what it takes.
Output of the amp to the + input (with very high value resistor)
actual value depends on resistors in the sensor and reference but
usually 100Ks to meg ohms.

Frequently a resistor in series with a pot to ground on the output
will be used to take a small voltage off the output and gives an
adjustable hysteresis to feed back to the non inverting input. Cheap
and dirty is a high value resistor from out to non-inverting.
--

Posted by Eeyore on June 5, 2009, 5:51 am


default wrote:

> >> You'll need to introduce some hysteresis by connecting a large-valued
> >> resistor form the output to the + input.
> This is an op amp?

No. An LM393 is a dual comparator

Graham

due to the hugely increased level of spam please make the obvious adjustment
to my email address



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