Well, not "beads", chips rather. Multilayer.
A typical 2k in 1206 size, will saturate at a few 10s of mA, taking down about half (but not all of) the step in question.
Tim
Well, not "beads", chips rather. Multilayer.
A typical 2k in 1206 size, will saturate at a few 10s of mA, taking down about half (but not all of) the step in question.
Tim
-- Seven Transistor Labs, LLC Electrical Engineering Consultation and Contract Design Website: https://www.seventransistorlabs.com/
Mmmh. I have a few 1206 ferrite beads in stock. I'll measure them too.
Jeroen Belleman
Digikey 490-1051-1-ND. For the sim, I used a part in the standard LT Spice library, a Wurth 2.6K thing.
The native inductance of beads is only loosely correlated with 100 MHz impedance, but I should be OK.
Wurth is sure a weird company.
-- John Larkin Highland Technology, Inc lunatic fringe electronics
Worse so for high impedances, because the peak is closer to, or below,
100MHz. Typicallly the impedance on the slope of the peak is about 1/10 to 1/100 of the impedance given by the LF inductance.LF inductance isn't even a useful metric for ferrite beads; the peak Q might be 5 or 10 somewhere in the 100kHz range.
They have some well documented products, a lot of awfully expensive products, and a few undocumented products. I put in a CMC recently that "doesn't exist". Their website is a mess.
Tim
-- Seven Transistor Labs, LLC Electrical Engineering Consultation and Contract Design Website: https://www.seventransistorlabs.com/
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