I=92 looking at the step response of a photodiode (PD). I=92m stepping the current into a LED such that the step doubles the photo current from the PD. (I=92m not starting with the LED off, but on slightly.) Here=92s a =91scope shot. The bottom trace in the PD response. (The top is the voltage step to the LED (through 100 ohms)... AC coupled to get rid of a big DC offset.)
There is this long tail on the step response. Here=92s the same picture with the timebase slowed down.
Looks something like a 2-2.5 us tail on the step.
What=92s it caused by? I first thought it was perhaps heating of the LED during the step. But I was reading =93Photodetectors=94 by S. Donati, over the weekend. In Chapter 5 he talks about two sets of photo- generated carriers the majority are made in the depletion layer, and travel with the drift speed, (times in the nano-second range.) The second smaller set are those generated in the doped region. If they are within a diffusion length of the depletion region then these have a chance of adding to the photocurrent. Donati says that these have a time constant in the microsecond range! I wonder if this is what I am seeing?
I looked at the step response with a different color LED. (you expect more absorption in the doped region with shorter wavelength light.) So here is the pulse response from a 635 nm red and 594 nm Amber LED.
Any other ideas how I might determine if that's what I'm seeing...
Oh, the PD is a OSI-optoelectroncs PIN-3CD (3.2mm^2 area) reversed biased at ~12V.
George H.