No. Not without series/parallel combinations. Or, what you can get, will not be a Bessel type (despite Bessel being the lowest Q of common types).
You can fix one component kind in an RC active filter, because impedance doesn't matter. This is a consequence of the zero Zout, inf Zin asssumption of opamp circuits -- one which you need to maintain, hence needing GBW so-and-so above Fc. In an LC filter, Zin must match Zout, so a similar condition is not possible.
Now... if you're really serious about this "full custom" business... you can use _transformers_, and any ratios and capacitors you like. ;-)
Mind that a transformer is three degrees of freedom (Lp, Ls, k), so this makes it considerably more complicated. Example: use LL instead of (or with) series L to tune series stages, or use it for zeroes so your bandpass is sharper on the skirts. (Note that, even if you make Lp, Ls very large with high-mu core material, LL is still a very relevant value.)
Coupled inductors are also great for building coupled resonator BPFs, but that's a synthesis method really only useful at higher Q (BW < 30% say), so not as applicable here.
Tim
--
Seven Transistor Labs, LLC
Electrical Engineering Consultation and Contract Design
Website: https://www.seventransistorlabs.com/
"Piotr Wyderski" wrote in message
news:p44t4n$rfi$1@node1.news.atman.pl...
> There is a lot of papers and even some ready-made calculators
> which can design an optimal LC filter for a given approximation.
> The problem is that the component values are crazy. While it is
> possible to create a tunable L, there is no such a luxury for the
> high C values. So the question is kind of opposite: how good
> a filter can be given the full custom L, but only predefined
> capacitors? Is there any systematic design procedure for such
> a case? I understand the deviation from the ideal curves, the
> filter should be "good enough".
>
> Say, having only 100n, 10n and 1n caps and Fc=75kHz, 3dB BW=50kHz,
> and 6th order, what should be the values of L to approximate
> a bandpass Bessel as well as possible?
>
> Best regards, Piotr