Is Gate threshold voltage tolerance the same at 0.25mA as 10A?

Hi

I am using this one:

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The VGS threshold at 250uA is between 1V and 3V, defined at 25 degrees

I use it to switch high current, so it is driven with 5V to turn it on

At VGS of 4.5V the max RDSon is defined to be 55mOhm

So is the +/-1V at 250uA also valid at high current, so for guaranteed 55mOhm needs a drive of 5.5V (4.5+1V)

For the temperature spread of VGS at low current it looks like 0.5V over the entire temperature range, but more like 0.3V at higher currents (fig 2)

So if I need guaranteed 55mOhm I have to go another 0.25V up to 5.75V?

Regards

Klaus

Reply to
Klaus Kragelund
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What do you mean by threshold?...

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:-)

At constant Vds, there is a one-to-one function between Vgs and Id. Vgs(th) is _a single point on that curve_, defined by the conditions specified (usually constant Id, and either fixed Vds, or Vds=Vgs i.e. diode strapped).

Whatever happens at other currents, needn't be related to this parameter.

You're asking if, the _spread_ in the parameter corresponds to the same spread, using a similar test but at higher current?

Possibly.

The transfer curve (Vgs to Id) should be more or less consistent between parts, in terms of its shape. Its slope will vary with device geometry, and its offset will vary with process (doping, gate oxide thickness, etc.). It's an offset-and-gain (y=mx+b) sort of situation, except it's not a straight line but a sloppy curve thing, but the change follows that pattern anyway.

Because the gain factor varies too, it's not the case that the Vgs(th) variation is due entirely to offset. Both offset and gain are baked into the figure.

But the same variation is baked into the Rds(on) max figure. For the same Vgs, Id and Tj, Rds(on) will always be less than that max. For more Vgs, it will also be reduced (you can use the Rds(on) vs. Vgs plot to estimate how much, of course, that will no longer be a strictly worst case condition).

So you don't have anything to worry about!

Tim

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Seven Transistor Labs, LLC 
Electrical Engineering Consultation and Contract Design 
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Reply to
Tim Williams

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