For this crystal: "
The crystal is on the right side of the board vertically between the two load capacitors, the bottom load capacitors trace is highlighted red. The board thickness is 1/16" and the trace width is 10mils.
datasheet: "
(digikey part#: SE2413CT-ND) (manufacturer part#: FC-135 32.7680KA-A3)
frequency: 32.768kHz load capacitance: 12.5pF
For selecting the load capacitors to use for the crystal oscillator circuit I am using the formula: CL = [(CL1 * CL2) / (CL1 + CL2)] + Cstray
I am wondering what the stray capacitance Cstray is. If I estimate
2pF for the above circuit then I get: [(21*21) / (21+21)] + 2 = 12.5pFAlso for this crystal: "
C12 and C13 are the load capacitors and the trace width is 10mil and the board thickness is 1/16"
datasheet: "
(digikey part#: 300-8206-1-ND) (manufacturer part#: ABM3B-16.000MHZ-10-1-U-T)
frequency: 16MHz load capacitance: 10pF
If Cstray is 2pF, then: [(16*16) / (16+16)] + 2 = 10pF
Would the two above crystal oscillator circuits have about 2pF Cstray given the board layout?
Also if the actual load capacitance is high, the frequency will be lower, and if the actual load capacitance is low, the frequency will be higher. Is there a formula to give the percent change in frequency for a given load capacitance mismatch?
What kind of error in frequency can I expect if I have an actual load capacitance that is 15pF instead of the specified 10pF for the 16MHz crystal?
cheers, Jamie