Question - How do I convert dBm into miniVolts?

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I have a specification says the power level at the transmitter's
antenna should be at +15 dBm. If I assume the antenna's impedance
is 50Ohm, can I calculate the peak to peak voltage to be

Vpp = { 2 * 50 * [10^(15/20)] }^0.5 = 16.8mV?




Re: Question - How do I convert dBm into miniVolts?



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 **  Errrr   -  no.

1 mW  at 50 ohms  =   sq rt  0.05  = 0. 224 volts rms.

+ 15 dB   =   5.62 times  0.224  =   1.26 volts rms

1.26 volts rms   =   3.56 volts  p-p.




............    Phil



Re: Question - How do I convert dBm into miniVolts?



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**Sounds suspiciously like an assignment question to me.


--
Trevor Wilson
www.rageaudio.com.au



Re: Question - How do I convert dBm into miniVolts?


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Phil's answer is correct. you are on the right track, but have made
several errors:

1) its power, so dBm = 10log(P/1mW) - you used 20log... which is correct
for voltage or current.

so you should have used 10^(15/10)*1mW = 31.6 *mW*

2) you have ignored the mW scalar, 1/1000

so you should have used 10^(15/10)*1/1000 = 0.0316 W

3) your 2* is wrong, *and* shouldnt be inside the square root.

= Phils 1.257V, which is the RMS voltage required
across 50 Ohms to generate 31.6mW = 15dBm

multiply by sqrt(2) to convert to 1.778 Volts peak

double it to get 3.556Vpp

Cheers
Terry

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